Pass function as argument in Java
Pass function as argument in Java
February 28, 2014
This is an example of passing function as argument in java. It kind of ugly but it can solve my duplicate code problem as below:
Before
public class BinaryTest {
public static void main(String[] args) {
byte[] bs = "gailo".getBytes();
System.out.println("oct: " + toOct(bs));
System.out.println("binary: " + toBin(bs));
System.out.println("hex: " + toHex(bs));
}
private static String toOct(byte[] bs) {
StringBuilder sb = new StringBuilder();
for (byte b : bs) {
sb.append(b);
sb.append(" ");
}
return sb.toString();
}
private static String toBin(byte[] bs) {
StringBuilder sb = new StringBuilder();
for (byte b : bs) {
sb.append(Integer.toBinaryString(b));
sb.append(" ");
}
return sb.toString();
}
private static String toHex(byte[] bs) {
StringBuilder sb = new StringBuilder();
for (byte b : bs) {
sb.append(Integer.toHexString(b));
sb.append(" ");
}
return sb.toString();
}
}After
import com.google.common.base.Function;
public class BinaryTest {
public static void main(String[] args) {
byte[] bs = "gailo".getBytes();
System.out.println("oct: " + toString(bs, new Function<Integer, String>() {
@Override
public String apply(Integer input) {
return input.toString();
}
}));
System.out.println("binary: " + toString(bs, new Function<Integer, String>() {
@Override
public String apply(Integer input) {
return Integer.toBinaryString(input);
}
}));
System.out.println("hex: " + toString(bs, new Function<Integer, String>() {
@Override
public String apply(Integer input) {
return Integer.toHexString(input);
}
}));
}
private static String toString(byte[] bs, Function<Integer, String> function) {
StringBuilder sb = new StringBuilder();
for (byte b : bs) {
sb.append(function.apply(new Integer(b)));
sb.append(" ");
}
return sb.toString();
}
}